
NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: DR thread from Nov-Dec '04
From: George Huxtable
Date: 2005 Jan 19, 12:13 +0000
From: George Huxtable
Date: 2005 Jan 19, 12:13 +0000
Doug isn't the first to have been caught out by our crazy convention of referring to wind directions by where the wind's coming from, not going to (quite opposite to the convention for currents). He has tried to clear matters up, but I think there's still a bit of confusion remaining. He wrote- >After reading my origonal post on this subject I noticed I wrote the set >discription incorrectly.I appologise for any confusion I caused and will >clear it up now. >If the wind is out of the north at 360 * T the set will be in the direction >of 180 * T. Perhaps Doug is referring the "set" of the wind here, which is presumably the direction the wind is travelling toward. It's not a familiar expression, to me. Or is Doug referring to the set of the wind-driven current here? >If the wind is on the starboard beam the resulting current will >push the vessel toward the south. Well, that would be true if the direction of the current set was indeed 180*T, and that would be true whatever part of the ship the wind was blowing on. But Doug will deduce, in the next sentence, that the wind-driven current set will be to the South-West, in the direction 220*T, not to the South, so that's the direction in which it will push the vessel. >That issue now being corrected the set of >the wind driven current will be in the direction of 220 * T,not 320 * T. >Again, 360 *T - 180 * T = 180 * T. 180* T + 40 *(to the right of the wind >direction)= 220 * T. Agreed. But there's another matter that's confusing. His original posting contained the passage- >The drift will be 2% of the true wind speed. >The set will be 40 * to the right of the true wind direction(Northern Hem.) >and reversed when used in the S.H. > >Ex: >The true wind speed is 20 knots sustained with the wind coming dead into the >starboard beam. >The ship's head is 270 * T .We'll make the true wind direction 360 * T to >meet the above condition. >The wind generated drift will be 0.2 knot. But surely if the wind speed was 20 knots then a drift of 2% of the wind speed would be 0.4 knots, not 0.2 knots. Have I got it right? As Doug says, at sea a small offset current is an important matter (more important still to us small-boat sailors, who only aim to travel through the water at 4 knots or so). Perhaps Doug might scrub-and-replace his original posting, with its later amendment, with another that's entirely self-consistent, to avoid losing the meaning of his message. I remember taking a short course on oceanography, 50 years ago, and one of the topics that has stuck in my mind ever since is the Ekman theory of wind drift, developed just 100 yearss ago, and using some ferocious (to me then) maths. Ekman deduced that in the Northern hemisphere the current at the surface was 45 degrees to the right of the wind, and deeper down it was further still around, to the right. The mechanism is similar to that which makes the wind spin in circles in storms and depressions, and is due to the rotation of the Earth. There is a return current, which allows the water that's shifted by the surface current, to flow back the other way at a deeper level, deeper even than Doug's ships. It's satisfying to think that Ekman's academic work is now saving fuel on the World's oceans. George ================================================================ contact George Huxtable by email at george@huxtable.u-net.com, by phone at 01865 820222 (from outside UK, +44 1865 820222), or by mail at 1 Sandy Lane, Southmoor, Abingdon, Oxon OX13 5HX, UK. ================================================================