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I'm in for the whole meal deal!

Thomas A. Sult, MD
Sent from iPhone

On Jan 30, 2010, at 1:48, Gary LaPook  wrote:

> I priced out the components today. The two inch plugs are $3.90,
> $7.80 for two. The threaded rod is $3.59 for 36 inches which I can
> cut to make three pieces long to make three locking devices.  A self
> locking nut is $0.45 and a regular nut is $0.11. So with sales tax
> the parts for the locking mechanism come to $10.40 plus postage. If
> anybody is interested let me know.
>
> gl
>
> Gary LaPook wrote:
>> If you want to use the locking device that I came up with and you
>> can't buy the components where you are I could purchase them here
>> and ship them to you. The plugs cost about five dollars each, you
>> need two of them, and I think the threaded rod was about the same.
>> I think it would cost about twenty dollars for all the components
>> including postage if anybody is interested.
>>
>> gl
>> Wolfgang Hasper wrote:
>>> I received a sample of those laminated paper tubes.
>>>
>>> The exterior surface is very smooth and even, rather matte than
>>> glossy. I am sure it can be used to put on printed scales without
>>> further treatment.
>>>
>>> By the way: I found white adhesive film in A4 size that can be
>>> used in a laser printer.
>>>
>>> the interior surface is glossy, due to production on a core tube.
>>> (it is a coiling production process. No noticeable seam or other
>>> irregularity from the coil end on the outside though.)
>>>
>>> For ease of transport and to save on cost there the tubes should
>>> be cut to length at the manufacturer's.
>>> They provide precise cuts to right-angles which I think is a huge
>>> benefit and valuable help for our futher work. I will shortly
>>> receive information on the cutting cost.
>>>
>>> As I find only now those lengths are not sufficiently known yet.
>>> RvR's paper gives account of the visible:
>>>
>>> inner tube        something > 230mm with 198 mm of scale
>>> intermediate tube    225 mm
>>> outer/cursor tube    222 mm (this is reliably the true length of
>>> the tube)
>>>
>>> The intermediate tube will for sure extend into the base and end
>>> just before the "upper" cursor cut-out (marked II). (assumed
>>> cursor tube on zero stop) So the inner tube is visible there.
>>>
>>> The inner tube itself will be long enough to be sufficiently
>>> stabilised when fully drawn out, yet short enough to leave some
>>> space for the locking mechanism down in the base region (when
>>> slide rule is fully closed)
>>>
>>> Assume the black base is a "cup" slipped on the end of the
>>> intermediate tube.
>>>
>>> I will make a sectional drawing to determine the missing lengths
>>> and post it for discussion. Any comments welcome.
>>> Would you please tell me if anybody wants to have non-HR lengths?
>>>
>>> Wolfgang
>>>
>>>
>>>
>>>
>>>
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