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    Re: Borrowed Bygrave
    From: Gary LaPook
    Date: 2016 Jan 15, 18:26 +0000

    Nope I can't since that is the only website I have. I only set it up in 
    response to the wild claims made by TIGHAR about where Earhart ended up, 
    TIGHAR has made a lot of money from contributions from a gullible public out 
    of those claims with the head guy paying himself $238,000 a year out of his 
    "tax exempt non-profit" which rubbed me the wrong way."
    
    gl
    --------------------------------------------
    On Fri, 1/15/16, Tom Sult  wrote:
    
     Subject: [NavList] Re: Borrowed Bygrave
     To: garylapook---.net
     Date: Friday, January 15, 2016, 7:57 AM
     
     Can
     you send your website?  Tsult---.com. When
     I google you I find lots of your stuff about  Amelia
     Erhardt but a general website I do not find. 
     
     Tom Sult, MDAuthor: JUST BE WELLjustbewell.info
     On Jan 15, 2016, at 03:57, Gary LaPook 
     wrote:
     
     If you
     read the rules for special cases in these photos of the
     Bygrave you will find that CPT Bygrave tells us how to
     compute the altitude when the declination is less than the
     lowest number on the scales. He tells us that  to find
     the altitude in this case that you interchange the
     declination and the assumed latitude since the astronomical
     triangle works from both ends, the altitudes, as calculated
     from either end (GP or AP,) must be the
     same. 
      BUT, he
     doesn't tell us how to find the azimuth!
     I had to
     invent a method for this situation and it is on my
     
    website.==============================================================================================When 
    declination is less than one
     degree you can't begin the computation the normal way to
     find "W" because you have to start the process
     with declination on the cotangent scale and this scale
     doesn't extend below 1º. So in this case you just skip
     the computation of "W" and simply set
     "W" equal to declination. Using this method you
     arrive at an azimuth that is not exact but is a close
     approximation and in the worst case I have found the azimuth
     is still within 0.9º of the true azimuth but most are much
     closer. If the declination is less than one degree and the
     latitude is also less than one degree, follow this procedure
     and also assume a latitude equal to one degree. After you
     have computed the Az you then follow the same procedure
     discussed above for azimuths exceeding 85º by interchanging
     the latitude and declination and then computing Hc which
     will produce an exact value of Hc.
     
     ====================================================
     gl
         
      
     From: Gary
     LaPook 
      To:
     garylapook---.net 
      Sent:
     Thursday, January 14, 2016 6:47 PM
      Subject:
     [NavList] Re: Borrowed Bygrave
        
     i took
     these photos at the Science Museum in London.gl
     
     
     
     
     
     Attached File: 
     
     (BygraveInstructions0001.jpg: Open
     and save)
     
     
     
     Attached File: 
     
     (BygraveInstructions0002.jpg: Open
     and save)
     
     
     
     Attached File: 
     
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     and save)
     
     
     
     Attached File: 
     
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     and save)
     
     
     
     Attached File: 
     
     (BygraveInstructions0005.jpg: Open
     and save)
     
     
     
     Attached File: 
     
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     Attached File: 
     
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     Attached File: 
     
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