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Re: Azimuth Formula Questions
From: John Simmonds
Date: 2005 Oct 23, 23:58 +1000
From: John Simmonds
Date: 2005 Oct 23, 23:58 +1000
the same formula will work for great circle sailings
enter departure as assumed position .. destination as LHA & Dec
John
On Sun, 23 Oct 2005 11:58:10 +0300, Marcel E. Tschudin wrote:
>�George, you suggested this formula to calculate the azimuth
>
>>�az = arctan (sin (hour angle) / (cos (hour angle) sin lat - cos
>>�lat tan dec))
>>
On Sun, 23 Oct 2005 11:58:10 +0300, Marcel E. Tschudin wrote:
>�George, you suggested this formula to calculate the azimuth
>
>>�az = arctan (sin (hour angle) / (cos (hour angle) sin lat - cos
>>�lat tan dec))
>>
<snip>
>>
>�Do you know of a formula with the same advantages as the one you
>�mentioned here in order to calculate the azimuth for the direction
>�between two locations on the globe? The spherical triangle formula
>�which I am using at present needs a lot of if-statements for
>�selecting the right quadrant. May be there does also exist a more
>�advantegeous formula to calculate this azimuth.
>
>�Marcel
>>
>�Do you know of a formula with the same advantages as the one you
>�mentioned here in order to calculate the azimuth for the direction
>�between two locations on the globe? The spherical triangle formula
>�which I am using at present needs a lot of if-statements for
>�selecting the right quadrant. May be there does also exist a more
>�advantegeous formula to calculate this azimuth.
>
>�Marcel
