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    Re: Astronomical Refraction: Computational Method for All Zenith Angles
    From: Marcel Tschudin
    Date: 2005 Aug 17, 17:25 +0300

    Correction refering my comment in the foregoing mail:
    
    > According to the curve shown on the page from Andrew Young
    > http://mintaka.sdsu.edu/GF/explain/optics/disp.html it would
    > correspond to a wavelength at the red end of the visible spectrum ....
    
    It actually corresponds to about 550nm, which is greenish yellow. This
    indicates then that the wrong value for alpha is really a misprint.
    
    Sorry for having misread the grap
    Marcel
    
    
    

       
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