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    Re: 3-Star Fix - "Canned Survival Problem"
    From: Greg R_
    Date: 2008 Jun 14, 01:54 -0700

    With the exception of the red numbers on the outside rings, your MB-2A
    computer looks remarkably similar to the Jeppesen CR series (CR-3,
    CR-6, etc.) - is it maybe a military version (or an earlier version)of
    the Jepp one?
    
    And I assume this isn't the other calculator that you alluded to
    earlier (Barger, or something similar?) - it's late and I can't find
    that particular post right now.
    
    --
    GregR
    
    
    
    
    --- "Gary J. LaPook"  wrote:
    
    > Gary J. LaPook wrote:
    > 
    > > Being the conscientious navigator that I am, I followed my usual 
    > > practice of memorizing some data from the 2008 Nautical Almanac so 
    > > that I would have it available for emergency use.
    > >
    > > The first thing I memorized was the GHA of Aires at 0000 Z January
    > 1, 
    > > 2008 which is 100� 01.9' and also remembering that Aires advances 
    > > 59.139' each day. With this information you can calculate GHA Aires
    > 
    > > for 0000 Z on June 9, 2008 which is the 161st day of the year but
    > is 
    > > only 160 days from January 1st. So multiplying 59.139' times 160
    > days 
    > > gives  157� 42.2'  to which you add the starting value of 100�
    > 01.9' 
    > > to come up with the GHA Aires on June 9th at 0000 Z of  257� 44.1'.
    > To 
    > > this you add the change of GHA for the time since 0000 Z (3 hours
    > 42 
    > > minutes 10 seconds for the Vega shot) by multiplying the time
    > interval 
    > > by the rate of change of 15.041� per hour making 55� 41.6' making
    > the 
    > > GHA Aires at the time of the Vega shot of 313 � 25.7'.
    > >
    > > I also memorized the SHAs and the Declinations of ten of the 
    > > navigation stars ( nobody could memorize all 57) which should be 
    > > enough for emergency use as tabulated for July 1st so that the
    > values 
    > > will be reasonable for the whole year. Fortunately this included
    > the 
    > > three stars used in this exercise. So now adding the SHA of Vega,
    > 80�  
    > > 41' we end up with the GHA of Vega of 34� 06.7' and using the D.R.
    > as 
    > > the A.P. we get an LHA of 274� 48' and the declination of 38� 47'
    > N. 
    > > (rounded to the whole minute)
    > >
    > > Using these values on my Bygrave slide rule (see attached work
    > sheet) 
    > > since I have no tables with me, I computed Hc of 23� 59'.
    > >
    > > The Hs given was 24� 05.5' Computing the dip correction in my head
    > of 
    > > 4.5' (the square root of 20 must be between 4 and 5 ) and applying
    > the 
    > > refraction correction of minus 2 gives an Ho of 23� 59' giving and 
    > > intercept of zero and an azimuth of  58.1 �.  I long ago memorized
    > the 
    > > refraction table for altitudes above 10� in The Air Almanac and in
    > H.O 
    > > 249, the cutoff values are 63-33-21-16-12-10� , zero above 63, 1
    > above 
    > > 33, 2 above 21, 3 above 16, 4 above 12 and 5 above 10.
    > >
    > > I used the same procedure for Spica and Pollux getting another zero
    > 
    > > intercept for Pollux, Zn of 290.2� and a  4 NM away for Spica with
    > a 
    > > Zn of 171.7�.
    > >
    > > Since I am on the road I do not have any of my plotting tools with
    > me 
    > > so I had to make do with what I found in my briefcase. I used my
    > MB-2A 
    > > flight computer since it had an azimuth scale and I used a pad of 
    > > paper  with a right angle at the corner as my straight edge for 
    > > plotting the LOPs. I used a tape measure from IKEA to measure the 
    > > length of the intercept (see photo.)  I plotted the LOPs and found
    > the 
    > > fix by bisecting the three angles giving a fix .4 NM west of the
    > A.P. 
    > > (D.R.) and 2.8 NM north of it. (Plotting a fix as a distance from
    > the 
    > > A.P. like this is common in aerial practice and it is often done on
    > an 
    > > E-6B.) Adding the 2.8 NM north to the D.R. latitude gives a fix 
    > > latitude of 34� 16' North. To convert the .4 NM west  to a
    > longitude 
    > > you divide the .4 NM by the cosine of the latitude, .82, to find
    > the 
    > > difference in longitude of  .5' so the fix longitude is 119� 19.5' 
    > > West (rounded to either 119� 19' or 20'.)  ( I got the cosine of
    > 34� 
    > > by finding the sine of 56� on the MB-2A sine scale, used for wind 
    > > correction calculations.)
    > >
    > > My fix might not be in agreement with others but I used a
    > refraction 
    > > table tabulated in whole minutes, I only memorized the stars' 
    > > positions to the nearest minute and I did not have any plotting
    > tools 
    > > to use but my position is certainly good enough for emergency 
    > > navigation and done without an almanac, tables or electrons.
    > >
    > > gl
    > > 1
    > >
    > > m_burkes@msn.com wrote:
    > >
    > >>Captain Lecky would be proud of those dividers ha! Speaking of
    > >>interpolation I have found a neat way to get around that pesky DSD
    > and
    > >>interpolation tables by using the aviation E6B computer or the
    > >>equivalent nautical slide rule. Essentially the set
    > up:d-value/60=d-
    > >>correction/declination minutes. Yes the calculator offers the
    > proof.
    > >>Mike Burkes
    > >>On Jun 12, 11:44 pm, Anabasi...@aol.com wrote:
    > >>  
    > >>
    > >>>Thanks for the nice exercise Greg.  I literally had to dust off
    > the  ship's
    > >>>Vol III of HO 229 and deflower a Plotting sheet 925 to work this
    > one  out.
    > >>>
    > >>>Since I was bereft of electronic gadgets, I did this with a
    > plotting sheet,  
    > >>>2 triangles, a pair of dividers, 2 books, a pencil, and small
    > piece of scratch
    > >>> paper (wouldn't have reams of paper in the Lifeboat).  I have
    > attached a  
    > >>>picture in to this message with the plot and the tools.
    > >>>
    > >>>My Lat is a bit lower (plotting or math error?).  I used an
    > assumed  position
    > >>>method and HO 229.  I had to assume we were drifting and no 
    > current (didn't
    > >>>advance or retard the lines).  I had not done a full HO 229  paper
    > reduction
    > >>>of a star in many years, and I had to think a second to remember 
    > how to use
    > >>>the interpolation pages on the inside covers for the declination 
    > interpolation.
    > >>> I usually whip those off with the calculator.  Still,  I got
    > pretty close to
    > >>>the computer solutions with Lat 34deg 11.9' N and  Longitude
    > 119deg 16.0'W.
    > >>>
    > >>>As to how you would get an Eastern sight on the west coast, you
    > would have  2
    > >>>options in general.  The first would be a back sight.  This would
    > be  
    > >>>particularly difficult with a regular sextant at such a low
    > altitude.  The  other
    > >>>option would be to use a bubble sight tube or other artificial 
    > horizon.  If you
    > >>>were across a bay, you could also use a dip short of  the horizon
    > table.  
    > >>>That's all I can think of at the moment.
    > >>>
    > >>>Jeremy
    > >>>
    > >>>**************Vote for your city's best dining and nightlife.
    > City's Best
    > >>>2008.      (http://citysbest.aol.com?ncid=aolacg00050000000102)
    > >>>
    > >>> gregExerPlot.jpg.JPG
    > >>>182KViewDownload
    > >>>
    > >>> GregExerTools.jpg.JPG
    > >>>129KViewDownload
    > >>>    
    > >>>
    > >>
    > >>
    > >>  
    > >>
    > >
    > >
    > > >
    > 
    > 
    > > 
    > 
    
    
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