Welcome to the NavList Message Boards.


A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

Compose Your Message

Add Images & Files
    Re: 2016, June 14th Mars Lunars
    From: Sean C
    Date: 2016 Jun 15, 04:57 -0700


    Sorry for the late response, but I was tied up all day yesterday.

    You asked:

    What instrument and what scope magnification, if I may ask?

    Astra IIIb w/ 3.5x scope.

    You also wrote:

    In your graph, I don't understand what the dashed line represents, and I don't understand the points you've marked with squares and keyed as calculated distances. How were these calculated?

    I calculated the distances using the formula from your "easy lunars" page: cos-1(sin(Dec1)·sin(Dec2)+cos(Dec1)·cos(Dec2)·cos(GHA2-GHA1)), the same fomula used to calculate the distances for the whole hours preceeding and following the observations. I picked two times that would fall within my graph and I used a second Y-axis on the right to account for the difference in the arcminute range. (The difference doesn't really matter. It's the slope I'm after.) The dotted line represents the slope of the two calculated distances, adjusted for a best fit among the sextant distances. This method was discussed in David Burch's PDF on sight averaging linked to in Bob Goethe's post on Jul. 18th, 2015.

    The idea is that, at any given time, the actual slope of a body's changing alitude (or, in this case, apparent distance from the moon) can be calculated and compared with one's observations. Hopefully, this would yield a better analysis of possible errors than simply drawing an arbitrary best-fit slope through the sights. However, this isn't the first time that I've noticed the difference between that slope and the slope I get by using the error values from your online clearing app. My question was whether or not this is due to the fact that I'm trying to fit a slope from calculated geocentric distances to "pre-cleared" topocentric observations. It seems, perhaps ironically, that I would have actually been better off using an arbitrary slope in this case. Do you think I would get a more accurate fit if I somehow worked parallax back into the calculated distances, or instead used cleared distances in the graph, as opposed to raw sextant distances? Or is this method simply not suited to analyzing lunars?

    Hope that made sense. ;)


    -Sean C.

    Browse Files

    Drop Files


    What is NavList?

    Join NavList

    (please, no nicknames or handles)
    Do you want to receive all group messages by email?
    Yes No

    You can also join by posting. Your first on-topic post automatically makes you a member.

    Posting Code

    Enter the email address associated with your NavList messages. Your posting code will be emailed to you immediately.

    Email Settings

    Posting Code:

    Custom Index

    Start date: (yyyymm dd)
    End date: (yyyymm dd)

    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site